How much gas will be released during the thermal decomposition of 150 g of limestone?

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

When decomposing 1 mol of limestone, 1 mol of calcium oxide and 1 mol of carbon monoxide are obtained.

Let’s calculate the chemical amount of calcium carbonate. For this purpose, we divide its weight by its molar mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 150/100 = 1.5 mol;

Find the volume of 1.5 mol of carbon dioxide.

To do this, multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 1.5 x 22.4 = 33.6 liters;

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