How much gasoline is consumed in an internal combustion engine that drives a pump that draws 4 tons of oil from a depth of 1500m? Is the engine efficiency 30%?
Efficiency formula Ƞ = Apole / Qspent * 100%
Apole in our case will be equal to the product of the oil gravity by the depth:
A-useful = Ftyazh. * H = mgh, where g – gravitational acceleration, m – oil mass, h – depth.
The energy released during fuel combustion is calculated using the fuel combustion formula, i.e., we multiply the specific heat of combustion of the binzine by its mass:
Qexpended = q * M, where q – specific. warm combustion. gasoline, M is the mass of gasoline.
The final formula: Ƞ = mgh / qM * 100%, do not forget to convert the values to SI units when calculating.
Ƞ = (4000 * 10 * 1500) / (44 * 106 * M) * 100% = 30%
Further mathematical calculations, which result in:
M = (4000 * 10 * 1500) / (0.3 * 44 * 106)
M = 4.5KG
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