How much heat is needed to cool 200 g of aluminum from 80 degrees to 20 degrees? Specific heat of aluminum 920J / kg degrees?
Task data: m (mass of taken aluminum) = 200 g (0.2 kg); t0 (initial temperature) = 80 ºС; t (final temperature of aluminum) = 20 ºС.
Reference values: according to the condition Ca (specific heat of aluminum) = 920 J / (kg * K).
The amount of heat released during the cooling of the taken aluminum is determined by the formula: Q = Ca * m * (t0 – t).
Calculation: Q = 920 * 0.2 * (80 – 20) = 11 040 J.
Answer: When 200 grams of aluminum cools down, 11,040 J of heat will be released.
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