How much heat is required to boil 6 kg of water if the initial water temperature is 20 degrees.
| July 24, 2021 | education
Given:
m (mass of water) = 6 kg.
tн (initial water temperature) = 20 ºС.
Reference values:
C (specific heat of water) = 4200 J / (kg * K).
tк (boiling point of water) = 100 ºС.
Solution:
Formula for calculation:
Q = С * m * (tк – tн) = 4200 * 6 * (100 – 20) = 4200 * 6 * 80 = 2016000 J ≈ 2 MJ.
Answer: To boil 6 kg of water requires 2 MJ of heat.
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