Problem data: m (mass of the taken aluminum part) = 200 g (in SI m = 0.2 kg); t0 (initial temperature) = 20 ºС; t (final temperature of the aluminum part) = 100 ºС.
Constants: Ca (specific heat of aluminum) = 920 J / (kg * K).
The required heat for heating the taken aluminum part is calculated by the formula: Q = Ca * m * (t – t0).
Calculation: Q = 920 * 0.2 * (100 – 20) = 14.72 * 10 ^ 3 J = 14.72 kJ ..
Answer: To heat the taken aluminum part, 14.72 kJ of heat is required.
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