How much heat is required to turn 10 kg of ice into water at 0 degrees?

Ice is at the melting temperature and heat is consumed only for the transition of ice to a liquid state of aggregation; additional heating of water after transformation, according to the condition of the problem, is not required.

Q = λ * m, where λ is the specific heat of melting (for ice λ = 3.4 * 10 ^ 5 J / kg), m is the mass of ice (m = 10 kg).

Let’s calculate the heat:
Q = λ * m = 3.4 * 10 ^ 5 * 10 = 3.4 * 10 ^ 6 J = 34 MJ.

Answer: To convert 10 kg of ice into water, 34 MJ of heat is required.

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