How much heat must be spent to melt 4 kg of lead. Taken at the melting point?

How much heat must be spent to melt 4 kg of lead. Taken at the melting point? Specific heat of fusion heat of lead 0.25 * 10 ^ 5 J / kg

Given: m (mass of taken lead) = 4 kg; lead is at a temperature of 327.4 ° C (melting point).

Constants: according to the condition λ (specific heat of fusion of lead) = 0.25 * 10 ^ 5 J / kg.

Since lead is at the melting temperature, the heat expended will be equal to the product of its mass and the specific heat of fusion: Q = λ * m.

Calculation: Q = 0.25 * 10 ^ 5 * 4 = 1 * 10 ^ 5 J (100 kJ).

Answer: It is necessary to spend 100 kJ of heat.



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