How much heat will be released during the condensation of 300 g of alcohol?

univerkov | September 15, 2021 | education

Initial data: m (mass of alcohol) = 300 g.

Reference data: L (specific heat of vaporization of alcohol) = 0.9 * 10 ^ 6 J / kg.

SI system: m = 300 g = 0.3 kg.

The amount of heat that will be released during the condensation of alcohol is calculated by the formula: Q = L * m.

Let’s calculate: Q = 0.9 * 10 ^ 6 * 0.3 = 0.27 * 10 ^ 6 J = 270 kJ.

Answer: Upon condensation of 300 grams of alcohol, 270 kJ of heat will be released.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.