How much hydrogen can be obtained by the interaction of 250 g of methanol with metallic sodium?

Let’s make a chemical equation, not forgetting to put down the coefficients: 2СH3OH + 2Na = 2CH3ONa + H2.
Let us find the amount of the substance СH3OH: n (СН3OH) = 7.8125 mol.
Let’s find the amount of hydrogen substance: n (H2) = n (CH3OH) / 2 = 3.9 mol (seen from the equation).
Let’s find the volume of hydrogen: V (H2) = n * Vm = 87.36 liters.
Answer: V (H2) = 87.36 liters.

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