# How much hydrogen is formed when 130 mg of zinc is dissolved in hydrochloric acid?

July 27, 2021 | education

| The interaction of zinc with any acid, for example with hydrogen chloride, occurs in accordance with the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Regardless of the type of acid, dissolving 1 mole of metal releases 1 mole of gaseous hydrogen.

Let’s calculate the amount of substance contained in a sample of 130 milligrams of metal.

To do this, we find the ratio of its weight to molar mass.

N Zn = 130/1000/65 = 0.002 mol;

The same amount of hydrogen will be released during this interaction.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 0.002 x 22.4 = 0.0448 liters;

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