How much hydrogen is formed when 130 mg of zinc is dissolved in hydrochloric acid?

The interaction of zinc with any acid, for example with hydrogen chloride, occurs in accordance with the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Regardless of the type of acid, dissolving 1 mole of metal releases 1 mole of gaseous hydrogen.

Let’s calculate the amount of substance contained in a sample of 130 milligrams of metal.

To do this, we find the ratio of its weight to molar mass.

N Zn = 130/1000/65 = 0.002 mol;

The same amount of hydrogen will be released during this interaction.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 0.002 x 22.4 = 0.0448 liters;

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.