Metallic aluminum interacts with sulfuric acid. This results in the formation of aluminum sulfate and the evolution of hydrogen gas. The interaction is described by the following chemical equation.
2Al + 3H2SO4 = Al2 (SO4) 3 + 3 H2;
Let’s calculate the chemical amount of aluminum. For this purpose, we divide its weight by the weight of 1 mole of the substance.
M Al = 27 grams / mol;
N Al = 27/27 = 1 mol;
The chemical amount of released hydrogen will be: 1 x 3/2 = 1.5 mol
Let’s calculate its volume.
To do this, multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).
V H2 = 1.5 x 22.4 = 33.6 liters;
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