How much hydrogen is released when interacting with magnesium with a solution

How much hydrogen is released when interacting with magnesium with a solution of sulfuric acid weighing 490 grams and a concentration of 5%.

Magnesium dissolves in sulfuric acid solution. The reaction is described by the following chemical equation:

Mg + H2SO4 = MgSO4 + H2 ↑;

Let’s calculate the molar amount of sulfuric acid.

For this purpose, we divide its weight by the weight of 1 mole of acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 490 x 0.05 / 98 = 0.25 mol;

The same amount of hydrogen will be produced.

Let’s calculate the volume of hydrogen.

To do this, multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 0.25 x 22.4 = 5.6 liters;