How much hydrogen is required to react with 4 mol of lithium?

Data: νLi – the amount of the substance of the reacted lithium (νLi = 4 mol).

Const: Vm – molar volume (for the case of normal cond. Vm = 22.4 l / mol).

1) Equation: 2LiH (lithium hydride) = 2Li (lithium) + H2 (hydrogen) ↑.

2) Let’s calculate the amount of reacted substances: νH2 / νLi = 1/2 and νH2 = νLi / 2 = 4/2 = 2 mol.

3) The required volume of hydrogen: VH2 = νн2 * Vm = 2 * 22.4 = 44.8 liters.

Answer: For the reaction with 4 mol of lithium, 44.8 liters of hydrogen should have been required.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.