How much hydrogen is required to react with 67.2 liters of nitrogen?

Let’s find the volume of the evolved gas by the formula.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

1.Let’s find the amount of substance by the formula:

n = V: Vn

n = 67.2 L: 22.4 L / mol = 3 mol.

2. the equation of the reaction, we will find in what quantitative ratios the substances are.

N2 + 3H2 = 2NH3.

According to the reaction equation, there is 3 mol of hydrogen per mole of nitrogen. The substances are in quantitative ratios of 1: 3.

The amount of hydrogen substance should be 3 times more than the amount of nitrogen substance.

n (H2) = 3 mol x 3 = 9 mol.

3.Let’s find the volume of hydrogen.

V = 9 mol x 22.4 L / mol = 201.6 L.

Answer: 201.6 l.