# How much hydrogen will be released when 6.5 zinc reacts with hydrochloric acid?

September 12, 2021 | education

| **How much hydrogen will be released when 6.5 zinc reacts with hydrochloric acid? What is the volume of the released hydrogen?**

Zinc interacts with hydrochloric acid according to the following scheme:

Zn + 2HCl → ZnCl2 + H2;

To solve the problem, we calculate the molar amount of zinc.

M Zn = 65 grams / mol;

N Zn = 6.5 / 65 = 0.1 mol;

Therefore, the same amount of hydrogen will be obtained, equal to 0.1 mol.

Its volume will be:

V H2 = 22.4 x 0.1 = 2.24 liters;

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.