How much ice, taken at 0 ° C, will melt if it is given such an amount of heat that will be released during the condensation of water vapor, the mass of which is 8 kg, and the temperature is 100 ° C, at normal atmospheric pressure?
mp = 8 kg.
tl = 0 ° C.
tp = 100 ° C.
λl = 3.3 * 10 ^ 5 J / kg.
qp = 2.3 * 10 ^ 6 J / kg.
The amount of heat Qp, which is released during the condensation of water vapor, is determined by the formula: Qp = qp * mp, where qp is the specific heat of condensation of water vapor, mp is the mass of the vapor that has condensed.
The amount of heat Ql, which is necessary for melting ice, is determined by the formula: Ql = λl * ml, λl is the specific heat of melting of ice, ml is the mass of ice that has melted.
Qp = Ql.
qp * mp = λl * ml.
ml = qp * mp / λl.
ml = 2.3 * 10 ^ 6 J / kg * 8 kg / 3.3 * 10 ^ 5 J / kg = 55.75 kg.
Answer: water vapor can melt ml = 55.75 kg of ice.
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