# How much (modulo) the impulse of a car weighing 1 ton will change when its speed changes from 54 km / h to 72 km / h?

July 25, 2021 | education

| m = 1 t = 1000 kg.

V0 = 54 km / h = 15 m / s.

V = 72 km / h = 20 m / s.

Δp -?

The momentum of a car p is the product of its mass m by the speed of movement V: p = m * V.

Since the mass of the car does not change during its movement, then Δp = m * ΔV, where ΔV is the change in the speed of the car.

The increase in vehicle speed ΔV is expressed by the formula: ΔV = V – V0.

Δp = m * (V – V0).

Δp = 1000 kg * (20 m / s – 15 m / s) = 5000 kg * m / s.

Answer: the momentum of the car increased by Δp = 5000 kg * m / s.

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