How much (modulo) the impulse of a car weighing 1 ton will change when its speed changes from 54 km / h to 72 km / h?
July 25, 2021 | education
| m = 1 t = 1000 kg.
V0 = 54 km / h = 15 m / s.
V = 72 km / h = 20 m / s.
Δp -?
The momentum of a car p is the product of its mass m by the speed of movement V: p = m * V.
Since the mass of the car does not change during its movement, then Δp = m * ΔV, where ΔV is the change in the speed of the car.
The increase in vehicle speed ΔV is expressed by the formula: ΔV = V – V0.
Δp = m * (V – V0).
Δp = 1000 kg * (20 m / s – 15 m / s) = 5000 kg * m / s.
Answer: the momentum of the car increased by Δp = 5000 kg * m / s.
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