How much of a water substance decomposed under the influence of a direct electric current, if 67.2 m squared oxygen was formed? What is the volume of the resulting hydrogen?
V (O2) = 67.2 m3 = 67200 l
n (H2O) -?
V (H2) -?
1) Write the reaction equation:
2H2O = (electric current) => 2H2 ↑ + O2 ↑;
2) Calculate the amount of substance O2:
n (O2) = V (O2) / Vm = 67200 / 22.4 = 3000 mol;
3) Determine the amount of substance H2O:
n (H2O) = n (O2) * 2 = 3000 * 2 = 6000 mol;
4) Determine the amount of substance H2:
n (H2) = n (O2) * 2 = 3000 * 2 = 6000 mol;
5) Calculate the volume H2:
V (H2) = n (H2) * Vm = 6000 * 22.4 = 134,400 l = 134.4 m3.
Answer: The amount of H2O substance is 6000 mol; volume H2 – 134,400 l (134.4 m3).
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