How much orthophosphoric acid can be obtained by the interaction of 620 g of calcium

How much orthophosphoric acid can be obtained by the interaction of 620 g of calcium orthophosphate and 196 g of sulfuric acid, if the yield of the reaction product is 80%?

Ca3 (PO4) 2 + 3H2SО4 = 3CaSО4 + 2НЗРО4
v (Ca3 (PO4) 2) = 620/310 = 2 mol
v (H2SO4) = 196/98 = 2 mol
v (Ca3 (PO4) 2): v (H2SO4) = 1: 3
We count by sulfuric acid:
v (H3PO4): v (H2SO4) = 2: 3;
v (H3PО4) = 2 * 2/3 = 1.33 mol
m (H3P04) = 1.33 * 98 = 130.34 g
130.34 * 0.8 = 104.3 g
Answer: 104.3 g