1. Let’s write down the reaction equation:
2CO + O2 = 2CO2.
2. Find the amount of carbon monoxide (Vm – molar volume, constant equal to 22.4 l / mol):
n (CO) = V (CO) / Vm = 22.4 L / 22.4 L / mol = 1 mol.
3. According to the reaction equation, we find the amount and then the mass of oxygen:
n (O2) = 2n (CO) = 2 mol.
m (O2) = n (O2) * M (O2) = 2 mol * 32 g / mol = 64 g.
Answer: m (O2) = m (O2) =
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