How much oxygen is required for the oxidation of 1 mol of calcium?

Reaction equation: 2Ca + O2 = 2CaO
By reaction with 1 mole of oxygen, 2 moles of calcium react, which means 1/2 = n (O2) / 1. Hence n (O2) = 0.5 mole.
Let’s find the volume of oxygen by the formula: V = n * Vm, here Vm = 22.4 l / mol – molar volume, constant for all gases under normal conditions. V (O2) = 0.5 mol * 22.4 L / mol = 11.2 L.
Answer: the volume of oxygen is 11.2 liters.

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