How much oxygen is required to completely burn 2 moles of phosphorus? What mass of phosphorus (V) oxide is formed in this case?
The synthesis reaction of phosphorus oxide is described by the following chemical reaction equation:
4P + 5O2 = 2P2O5;
4 moles of phosphorus react with 5 moles of oxygen. In this reaction, 2 moles of phosphorus oxide are synthesized.
It is required to burn 2 moles of phosphorus.
To burn this amount of phosphorus, 2 x 5/4 = 2.5 mol of oxygen will be required.
Let’s calculate its volume.
1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.
The required volume of oxygen will be:
V O2 = 2.5 x 22.4 = 56 liters;
From this amount of phosphorus, it is possible to synthesize 2/2 = 1 mol of its oxide.
Let’s find its weight.
To do this, we multiply the amount of the substance by its molar mass.
M P2O5 = 31 x 2 + 16 x 5 = 142 grams / mol;
m P2O5 = 142 x 1 = 142 grams;
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.