How much oxygen will it take to oxidize carbon monoxide (||) with a volume of 26 liters?

The oxidation reaction of carbon monoxide is described by the following chemical reaction equation:

CO + ½ O2 = CO2;

1 mole of carbon monoxide reacts with ½ mole of oxygen. This synthesizes 1 mol of carbon dioxide.

Let’s determine the chemical amount of a substance contained in 26 liters of carbon monoxide.

To do this, we divide the volume of gas by the volume of 1 mole of gas.

N CO = 26 / 22.4 = 1.161 mol;

To oxidize such an amount of a substance, 1.161 / 2 = 0.581 mol of oxygen is needed.

Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V O2 = 0.581 x 22.4 = 13.014 liters;