How much salt will be released when potassium interacts with a 3.4 g solution of hydrogen sulfide acid?

Reaction equation: 2K + H2S = K2S + H2
According to the periodic table, we determine the molar mass of hydrogen sulfide: M (H2S) = 1 * 2 + 32 = 34 g / mol.
Let’s find the amount of hydrogen sulfide substance: n = m / M = 3.4 g / 34 g / mol = 0.1 mol.
According to the reaction equation, 1 mol of hydrogen sulfide forms 1 mol of potassium sulfide, which means n (H2S) = n (K2S) = 0.1 mol.
According to the periodic table, we determine the molar mass of potassium sulfide: M (K2S) = 39 * 2 + 32 = 110 g / mol.
Find the mass of salt: m = n * M = 0.1 mol * 110 g / mol = 11 g.
Answer: the mass of salt is 11 g.



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