How much sodium oxide needs to be dissolved in water to get 8 g of NaOH? How many times will the mass of sodium oxide be greater than the mass of water?
The interaction of sodium oxide with water occurs in accordance with the following chemical reaction equation:
Na2O + H2O = 2NaOH;
1 mole of oxide reacts with 1 mole of water. As a result, 2 moles of alkali are formed.
Let’s calculate the chemical amount of a substance that is contained in 8 grams of alkali.
M NaOH = 23 + 16 + 1 = 40 grams / mol;
N NaOH = 8/40 = 0.2 mol;
To prepare such an amount of alkali, you need to take 0.1 mol of sodium oxide and 0.1 mol of water.
Let’s calculate the masses of these substances.
M Na2O = 23 x 2 + 16 = 62 grams / mol;
m Na2O = 0.1 x 62 = 6.2 grams;
M H2O = 2 + 16 = 18 grams / mol;
m H2O = 0.1 x 18 = 1.8 grams;
Let’s calculate how many times the mass of sodium oxide will be greater than the mass of water.
K = m Na2O / m H2O = 6.2 / 1.8 = 3.44 times;
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.