How much substance and how much gas does 9.6 g of SO2 contain?

univerkov | August 23, 2021 | education

Given:
m (SO2) = 9.6 g

Find:
n (SO2) -?
V (SO2) -?

1) M (SO2) = Mr (SO2) = Ar (S) * N (S) + Ar (O) * N (O) = 32 * 1 + 16 * 2 = 64 g / mol;
2) n (SO2) = m (SO2) / M (SO2) = 9.6 / 64 = 0.15 mol;
3) V (SO2) = n (SO2) * Vm = 0.15 * 22.4 = 3.36 l.

Answer: The amount of substance SO2 is 0.15 mol; volume – 3.36 liters.

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