How much weight can be lifted with the help of the movable block if the rope is pulled with a force of 120N?

How much weight can be lifted with the help of the movable block if the rope is pulled with a force of 120N? What work will be done if the load is lifted to a height of 2.5 m?

With the help of the movable block, we can win in strength 2 times, therefore, the maximum weight (P = m x g) = 120 N x 2 = 240 N.
Now we derive the mass from the weight formula: m = P / g (constant equal to 10 m / s ^ 2); m = 240 N / 10 m / s ^ 2; m = 24 kg.
And useful = m x g x h. By assumption, h = 2.5 m, we found m, and g is a constant. Hence, A = 24 kg x 10 m / s ^ 2 x 2.5 m; A = 24 x 25 = 600 J.
Answer: 24 kg; 600 J.