How much will the temperature of water weighing 20 kg change if all the energy released during the combustion of gasoline weighing 20 g is transferred to it?
Q1 = Q2.
Q1 = q * m1, where q is the specific heat of combustion of gasoline (q = 4.6 * 10 ^ 7 J / kg), m1 is the mass of burned gasoline (m1 = 20 g = 0.02 kg).
Q2 = С * m2 * ∆t, where С is the specific heat capacity of water (С = 4200 J / (kg * K)), m is the mass of water (m = 20 kg), ∆t is the change in water temperature (ºС).
Let us express and calculate the change in water temperature:
q * m1 = С * m2 * ∆t.
∆t = q * m1 / (С * m2) = 4.6 * 10 ^ 7 * 0.02 / (4200 * 20) ≈ 11 ºС.
Answer: The water temperature will increase by 11 ºС.
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