# How much will the temperature of water weighing 20 kg change if all the energy released during the combustion

How much will the temperature of water weighing 20 kg change if all the energy released during the combustion of gasoline weighing 20 g is transferred to it?

Q1 = Q2.

Q1 = q * m1, where q is the specific heat of combustion of gasoline (q = 4.6 * 10 ^ 7 J / kg), m1 is the mass of burned gasoline (m1 = 20 g = 0.02 kg).

Q2 = С * m2 * ∆t, where С is the specific heat capacity of water (С = 4200 J / (kg * K)), m is the mass of water (m = 20 kg), ∆t is the change in water temperature (ºС).

Let us express and calculate the change in water temperature:

q * m1 = С * m2 * ∆t.

∆t = q * m1 / (С * m2) = 4.6 * 10 ^ 7 * 0.02 / (4200 * 20) ≈ 11 ºС.

Answer: The water temperature will increase by 11 ºС.

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