How to calculate the amount of heat required to melt 100 g of ice?

Given:

m = 100 grams is the mass of ice;

q = 330 kJ / kg = 330,000 Joule / kilogram is the specific heat of melting of ice (constant for physics problems).

It is required to determine Q (Joule) – the amount of energy required to melt ice of mass m.

Since the condition of the problem is not specified, we assume that the ice is at the melting temperature (0 degrees Celsius) and additional heating is not required.

Then, let’s convert the units of mass measurement from grams to kilograms:

m = 100 grams = 100 * 10-3 = 0.1 kilograms.

The amount of heat will be equal to:

Q = q * m = 330,000 * 0.1 = 33,000 Joules = 33 kJ.

Answer: to melt ice, a heat of 33 kJ is required.