How to calculate the amount of video memory required to store a 512 by 268 graphics

How to calculate the amount of video memory required to store a 512 by 268 graphics image with 16,777,216 displayable colors

First, you need to determine how many bits of information one color occupies.

For this we use the following formula:

N = 2 ^ i

N is the number of colors in the palette.

i – volume of one color.

16777216 = 2 ^ 24

i = 24 bits.

Determine the total number of pixels in this image.

To do this, we multiply its resolution among ourselves.

512 * 268 = 137,216 pixels.

Find the volume of the image in bits.

137216 * 24 = 3293184 bits.

In Kbytes we get:

3293184 / (1024 * 8) = 401.8 KB.

Answer:

Requires 401.8 KB of video memory.



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