How to calculate the mass of water that is necessary for the complete interaction of 2.3 g of Na.

1.the interaction of sodium with water occurs according to the equation:

2Na + 2H2O = 2NaOH + H2 ↑;

2.To proceed to calculating the determination of the mass of water, you need to find the amount of the reagent with known data, in this problem the mass of sodium is known, we will calculate its chemical amount:

n (Na) = m (Na): M (Na);

n (Na) = 2.3: 23 = 0.1;

3. according to the equation, we look at how the coefficients in front of sodium and water relate, they are equal, which means:

n (H2O) = n (Na) = 0.1;

4.The mass of water is calculated by the formula:

m (H2O) = n (H2O) * M (H2O);

M (H2O) = 2 * 1 + 16 = 18 g / mol;

m (H2O) = 0.1 * 18 = 1.8 g.

Answer: 1.8 g.