How will the force of universal gravity change if the mass of one of the interacting bodies decreases 6 times, and the distance between the centers decreases 2 times.
m1 = 6 * m2.
R1 = 2 * R2.
Ftyag1 / Ftyag2 -?
The force of universal gravitation is determined by the formula: Ftyag = G * m * M / R ^ 2, where G is the gravitational constant, m, M are the masses of interacting bodies, R is the distance between interacting bodies.
Ftyag1 = G * m1 * M / R1 ^ 2 = G * 6 * m2 * M / (2 * R2) ^ 2 = 6 * G * m2 * M / 4 * R2 ^ 2 = 3 * G * m2 * M / 2 * R2 ^ 2
Ftyag2 = G * m2 * M / R2 ^ 2.
Ftyag1 / Ftyag2 = 3 * G * m2 * M / 2 * R2 ^ 2: G * m2 * M / R2 ^ 2 = 3/2 = 1.5.
Answer: the force of interaction will decrease by 1.5 times: Ftyag1 / Ftyag2 = 1.5.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.