How will the force of universal gravity change if the mass of one of the interacting bodies decreases

How will the force of universal gravity change if the mass of one of the interacting bodies decreases 6 times, and the distance between the centers decreases 2 times.

m1 = 6 * m2.
R1 = 2 * R2.
Ftyag1 / Ftyag2 -?
The force of universal gravitation is determined by the formula: Ftyag = G * m * M / R ^ 2, where G is the gravitational constant, m, M are the masses of interacting bodies, R is the distance between interacting bodies.
Ftyag1 = G * m1 * M / R1 ^ 2 = G * 6 * m2 * M / (2 * R2) ^ 2 = 6 * G * m2 * M / 4 * R2 ^ 2 = 3 * G * m2 * M / 2 * R2 ^ 2
Ftyag2 = G * m2 * M / R2 ^ 2.
Ftyag1 / Ftyag2 = 3 * G * m2 * M / 2 * R2 ^ 2: G * m2 * M / R2 ^ 2 = 3/2 = 1.5.
Answer: the force of interaction will decrease by 1.5 times: Ftyag1 / Ftyag2 = 1.5.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.