# How will the impulse of a car weighing 1 tonne change with an increase in its speed from V1 = 6 km / h

How will the impulse of a car weighing 1 tonne change with an increase in its speed from V1 = 6 km / h to V2 = 72 km / h.

Given:

m = 1 ton = 1000 kilograms – vehicle weight;

v1 = 6 km / h = 1.7 m / s – initial vehicle speed;

v2 = 72 km / h = 20 m / s – the final speed of the vehicle.

It is required to determine P2 / P1 – how the momentum of the car will change with increasing speed.

In the first case, the momentum of the car will be equal to:

P1 = m * v1 = 1000 * 1.7 = 1700 kg * m / s.

In the second case, the momentum of the car will be equal to:

P2 = m * v2 = 1000 * 20 = 20,000 kg * m / s.

Then:

P2 / P1 = 20,000 / 1700 = 11.8 times.

Answer: the momentum of the car will increase by 11.8 times.

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