Hydrochloric acid was added to a 10% potassium carbonate solution. In this case, a gas with a volume of 11.2 L was released. Determine the mass of the potassium carbonate solution.
V (gas) = 11.2 l
w% (K2CO3) = 10%
m (K2CO3) -?
K2CO3 + 2HCl = 2KCl + CO2 + H2O, – we solve the problem based on the composed reaction equation:
1) Find the amount of carbon dioxide. released during the reaction:
n (CO2) = V: Vm = 11.2 L: 22.4 L / mol = 0.5 mol
2) We compose a logical expression:
if 1 mol of K2CO3 gives 1 mol of CO2,
then x mol of K2CO3 will give 0.5 mol of CO2,
then x = 0.5 mol.
3) Find the mass of potassium carbonate that has reacted:
m (K2CO3) = n * M = 0.5 mol * 138 g / mol = 69 g.
4) Find the mass of the entire potassium carbonate solution:
m (solution K2CO3) = 69 g: 0.1 = 690 g.
Answer: m (solution K2CO3) = 690 g.
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