If a triangle has one acute angle, then the sum of the other two angles exceeds 90 degrees. Why?

Let in a triangle ABC <A <90 ° (acute angle), then the sum (<B + <C) <90 °. Let’s prove: subtract the angle that is less than 90 ° from the sum of the angles of the triangle, we get an angle greater than 90 °, or 180 ° – (<90 °)> 90 °.

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