1. Find the mass of water:
m (H2O) = V (H2O) * ρ (H2O) = 5000 * 1 = 5000 g.
2. Determine the mass of the solution:
m (solution) = m (H2O) + m (CuSO4 * 5H2O) = 5000 + 500 = 5500 g.
3. Let’s calculate the chemical amount of copper sulfate:
n (CuSO4 * 5H2O) = m (CuSO4 * 5H2O): M (CuSO4 * 5H2O);
M (CuSO4 * 5H2O) = 64 + 32 + 4 * 16 + 5 * 18 = 250 g / mol;
n (CuSO4 * 5H2O) = 500: 250 = 2 mol.
4. The amount of copper sulfate is the same as the amount of copper sulfate:
n (CuSO4) = n (CuSO4 * 5H2O) = 2 mol.
5. Set the mass of sulfate:
m (CuSO4) = n (CuSO4) * M (CuSO4);
M (CuSO4) = 64 + 32 + 4 * 16 = 160 g / mol;
m (CuSO4) = 2 * 160 = 320 g.
6. Let’s calculate the mass fraction of salt:
w (CuSO4) = m (CuSO4): m (solution) = 320: 5500 = 0.0582 or 5.82%.
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