In 5 s after the start of movement, the train acquires a speed of 1 m / s. How long does it take

In 5 s after the start of movement, the train acquires a speed of 1 m / s. How long does it take for the train (from the start of movement) to increase its speed 6 times, moving with the same acceleration?

Given: t1 (first acceleration time) = 5 s; V1 (first acquired speed) = 1 m / s; V2 (required speed of movement) = 6V1 = 6 m / s; uniformly accelerated motion.

1) Determine the constant acceleration of a given train: a = (V1 – V0) / t1 = (1 – 0) / 5 = 0.2 m / s2.

2) We calculate the duration of acceleration to a speed of 6 m / s from the beginning of the movement: t2 = (V2 – V0) / a = (6 – 0) / 0.2 = 30 s.

Answer: The target train will reach a speed of 6 m / s 30 seconds after it starts moving.