In a copper saucepan weighing 1.6 kg. There is 2.3 kg. Water. How much heat is required to heat a pot of water from 10 C to 100 C.
Data: m1 (mass of a copper pan) = 1.6 kg; m2 (mass of water) = 2.3 kg; t1 (initial temperature of the pot with water) = 10 ºС; t2 (end temperature) = 100 ºС.
Reference data: C1 (specific heat capacity of copper) = 400 J / (kg * ºС); С2 (specific heat capacity of water) = 4200 J / (kg * ºС).
The required amount of heat is determined by the formula: Q = Q1 + Q2 = C1 * m1 * (t2 – t1) + C2 * m2 * (t2 – t1) = (C1 * m1 + C2 * m2) * (t2 – t1).
Calculation: Q = (400 * 1.6 + 4200 * 2.3) * (100 – 10) = 972 000 J (972 kJ).
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