# In a hydraulic machine, the cross-sectional areas are 1:10. A body weighing 5 kg was placed on a small piston.

In a hydraulic machine, the cross-sectional areas are 1:10. A body weighing 5 kg was placed on a small piston. How much pressure must be applied to the larger piston to keep the system in balance.

To find the value of the force with which it is required to act on the larger piston of the specified hydraulic machine, we use the proportion: Fbp / Fmp = Fbp / (m * g) = Sbp / Smp, from where we express: Fbp = m * g * Sbp / Smp.

Variables and constants: m – body weight on a small piston (m = 5 kg); g – acceleration due to gravity (g ≈ 10 m / s2); Sbp / Smp – ratio of piston areas (Sbp / Smp = 10).

Let’s perform the calculation: Fbp = m * g * Sbp / Smp = 5 * 10 * 10 = 500 N.

Answer: The larger piston of the specified hydraulic machine must be pressed with a force of 500 N.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.