In a magnetic field with an induction of 0.04 T, an electric charge of 10 ^ -10 C moves at a speed of 200 m / s.

In a magnetic field with an induction of 0.04 T, an electric charge of 10 ^ -10 C moves at a speed of 200 m / s. What is the force F acting on the charge from the side of the magnetic field if the velocity vector v of the charge movement is perpendicular to the vector B of the magnetic field induction?

A charged particle moving in a magnetic field is acted upon by the Lorentz force.

The Lorentz force can be calculated by the formula F = q * v * B * sin (a), where q is the particle charge, v is the particle velocity, B is the magnetic field induction, a is the angle between the direction of the velocity and the direction of the magnetic induction vector.

Let us calculate the Lorentz force according to the problem conditions:

if the velocity vector is perpendicular to the magnetic induction vector, then the angle a = 90 °,

sin 90 ° = 1,

F = 10 * 10 ^ (- 10) C * 200 m / s * 0.04 T * sin 90 ° = 80 * 10 ^ (- 10) = 8 * 10 ^ (- 9) N.