In a rectangular trapezoid, the bases are 05 and 17 cm, and the large side side is 13 cm, find the area of the trapezoid.

Let’s draw the height of the CH trapezoid. The formed quadrangle ABSN is a rectangle, since AB and CH are perpendicular to the bases of the trapezoid.

Then AH = BC = 5 m.

The length of the segment DH = AD – AH = 17 – 5 = 12 cm.

From the right-angled triangle СDН, we determine the length of the leg СН.

CH ^ 2 = CD ^ 2 – DH ^ 2 = 169 – 144 = 25.

CH = 5 cm.

Determine the area of the trapezoid.

Savsd = (ВС + АD) * СН / 2 = (5 + 17) * 5/2 = 55 cm2.

Answer: The area of the trapezoid is 55 cm2.



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