The MOC triangle is rectangular, then, according to the Pythagorean theorem, OC ^ 2 = MC ^ 2 – MO ^ 2 = 20 ^ 2 – 16 ^ 2 = 400 – 256 = 144.
OC = 12 cm.
At the base of a regular pyramid is a square, the diagonals of which, at point O, are halved. Then AC = BD = OC * 2 = 12 * 2 = 24 cm.
Answer: The diagonal of the base is 24 cm.
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