In a regular quadrangular pyramid, the lateral rib is 20 cm, and the height is 16 cm. find the diagonal of the base.

The MOC triangle is rectangular, then, according to the Pythagorean theorem, OC ^ 2 = MC ^ 2 – MO ^ 2 = 20 ^ 2 – 16 ^ 2 = 400 – 256 = 144.

OC = 12 cm.

At the base of a regular pyramid is a square, the diagonals of which, at point O, are halved. Then AC = BD = OC * 2 = 12 * 2 = 24 cm.

Answer: The diagonal of the base is 24 cm.



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