Since triangle ABC is rectangular, and CD is the median drawn to the hypotenuse, the length of the median is equal to half the length of the hypotenuse.
CD = AB / 2.
AB = 2 * CD = 2 * 5.3 = 10.6 cm.
The BCD triangle is isosceles with the BC base, then the angle DCB = DBC.
In the triangle ABC, CosB = BC / AB = 4.7 / 10.6 = 0.44.
Angle ABC = DCB = arcos0.44 = 63.5.
Answer: The value of the angle DCB is equal to 63.5.
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