In a right-angled triangle ABC (angle C = 90 degrees) CD is the median. Find the angle DCB, there is CD = 5.3, BC = 4.7.

Since triangle ABC is rectangular, and CD is the median drawn to the hypotenuse, the length of the median is equal to half the length of the hypotenuse.

CD = AB / 2.

AB = 2 * CD = 2 * 5.3 = 10.6 cm.

The BCD triangle is isosceles with the BC base, then the angle DCB = DBC.

In the triangle ABC, CosB = BC / AB = 4.7 / 10.6 = 0.44.

Angle ABC = DCB = arcos0.44 = 63.5.

Answer: The value of the angle DCB is equal to 63.5.

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