In a right-angled triangle ABC, angle C is 30 degrees, leg AB = 2. Find the second leg AC, hypotenuse BC, angle B.

In a right-angled triangle ABC tgC = AB / AC.

AC = AB / tg30 = 2 / (√3 / 3) = 6 / √3 = 2 * √3 cm.

The AB leg lies opposite an angle of 30, then BC = 2 * AB = 2 * 2 = 4 cm.

Angle ABC = (90 – AСB) = (90 – 3) = 60.

Answer: The length of the second leg is 2 * √3 cm, the hypotenuse is 4 cm, the angle B is 60.



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