In a right-angled triangle ABC, the angle is C = 90 degrees. The BC leg is 2 times less than the hypotenuse. What is the degree measure of the angle opposite this leg?
Let the length of the hypotenuse AB be equal to X cm, then, by condition, the length of the leg BC = AB / 2 = X / 2.
The sine of an acute angle of a right triangle is the ratio of the adjacent leg to the hypotenuse of the triangle.
SinCAB = BC / AB = (X / 2) / X = 1/2.
Angle CAB = Arcsin (1/2) = 30.
Answer: The CAB angle is 30.
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