In a right-angled triangle, one of the legs is equal to 10 and the acute angle lying opposite

In a right-angled triangle, one of the legs is equal to 10 and the acute angle lying opposite it is equal to 45 °. find the area of the triangle.

Let the angle ABC = 45, leg BC = 10 cm.

In a right-angled triangle, the sum of the acute angles is 90, then the angle BAC = (90 – ABC) = (90 – 45) = 45.

Since the acute angles of a right-angled triangle are equal, the ABC triangle is right-angled and isosceles, AC = BC = 10 cm.

Then Savs = BC * AC / 2 = 10 * 10/2 = 50 cm2.

Answer: The area of the triangle is 50 cm2.