In a triangle ABC and A’B’C ‘AB = 3AB, AC: A’C’ = 1: 3, angle A = angle A ‘. If the area of the triangle A’B’C ‘is 27 cm2, then the area ABC is equal to.
Let’s introduce the variable x, which will be one part, that is, AC: A’C ‘= x: 3 * x.
If A’B ‘= 3AB, 3AC = A’C’, and A = A ‘, then the triangles are proportional to each other. That is, A’B ‘* B’C’ * C’A ‘= 3AB * 3BC * 3CB = 27.
Let’s find the area ABC: 3AB * 3BC * 3CB = 27; AB * BC * CB = 1.
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