In a triangle, one of the sides is 10, the other is 12, and the angle between them is 30 degrees. Find the area of the triangle.

Given:
∆ABS;
a = 10;
b = 12;
∠C = 30 °;
Solution:
The area of a triangle is equal to half the product of the sides by the angle between these sides, which can be written in the form of the formula:
S = ½ * a * b * Sin C;
where:
a and b are the sides of the triangle;
∠C is the angle between these sides.
S = ½ * 10 * 12 * Sin 30 ° = ½ * 10 * 12 * ½ = 5 * 6 = 30;
Sin 30 ° = 1/2;
Answer: 30




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