In a triangle with sides 6m, 8m and 10m, a bisector was drawn to the 8m side.
September 29, 2021 | education
| In a triangle with sides 6m, 8m and 10m, a bisector was drawn to the 8m side. Find the segments into which the bisector divides this side.
Let the length of the segment AM = X cm, then the length of the segment CM = (8 – X) cm.
To solve the problem, we apply the property of the bisector of the angle of a triangle, according to which it divides the opposite side of the triangle into segments proportional to the adjacent sides.
BC / CM = AB / AM.
10 / (8 – X) = 6 / X.
10 * X = 6 * (8 – X).
10 * X = 48 – 6 * X.
16 * X = 48.
X = AM = 48/16 = 3 cm.
Then CM = 8 – 3 = 5 cm.
Answer: The bisector divides the side into 5 cm and 3 cm segments.
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