In an ideal heat engine, the temperature of the heater is 250 degrees Celsius, and the temperature of the refrigerator is 0 degrees Celsius. How long did it take for the gas to deliver 100 kJ of heat to the refrigerator? How much heat did the gas get from the heater?
Data: Тн (abs. Heater temperature) = 523 К (250 ºС); Тх (abs. Refrigerator temperature) = 273 К (0 ºС); Qx (heat received by the refrigerator for some time) = 100 kJ.
1) The efficiency of the heat engine taken: η = 1 – Тх / Тн = 1 – 273/523 = 0.478 (47.8%).
2) Heat received by the working gas from the heater: Qн = Qх / (1 – η) = 100 / (1 – 0.478) = 191.575 kJ ≈ 192 kJ.
Answer: D) The working gas received 192 kJ of heat from the heater.
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