# In an ideal heat engine, the temperature of the heater is 250 degrees Celsius

In an ideal heat engine, the temperature of the heater is 250 degrees Celsius, and the temperature of the refrigerator is 0 degrees Celsius. How long did it take for the gas to deliver 100 kJ of heat to the refrigerator? How much heat did the gas get from the heater?

Data: Тн (abs. Heater temperature) = 523 К (250 ºС); Тх (abs. Refrigerator temperature) = 273 К (0 ºС); Qx (heat received by the refrigerator for some time) = 100 kJ.

1) The efficiency of the heat engine taken: η = 1 – Тх / Тн = 1 – 273/523 = 0.478 (47.8%).

2) Heat received by the working gas from the heater: Qн = Qх / (1 – η) = 100 / (1 – 0.478) = 191.575 kJ ≈ 192 kJ.

Answer: D) The working gas received 192 kJ of heat from the heater.

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